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u^2-54u+245=0
a = 1; b = -54; c = +245;
Δ = b2-4ac
Δ = -542-4·1·245
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-44}{2*1}=\frac{10}{2} =5 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+44}{2*1}=\frac{98}{2} =49 $
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